若m>0,n>0,m+n=1,证明:(m+1/m)^2+(n+1/n)^2>=25/2

来源:百度知道 编辑:UC知道 时间:2024/05/23 15:20:32
如题

证明:
(m+1/m)^2+(n+1/n)^2
=m^2+2+1/m^2+n^2+2+1/n^2
=(m^2+n^2)+(1/m^2+1/n^2)+4
=(m^2+n^2)+(m^2+n^2)/(m^2*n^2)+4
=(m^2+n^2)[1+1/(mn)^2]+4
=[(m+n)^2-2mn][1+1/(mn)^2]+4
=(1-2mn)[1+1/(mn)^2]+4
由均值不等式:mn<=[(m+n)/2]^2=1/4
因此
1-2mn>=1-2*(1/4)=1/2
1+1/(mn)^2>=1+1/(1/4)^2=17
所以
(m+1/m)^2+(n+1/n)^2
= (1-2mn)[1+1/(mn)^2]+4
>=(1/2)*17+4
= 25/2
证完